web安全的题，为了找key随手写的程序，无处安放，姑且贴上来。

1 # -*- coding: UTF-8 -*- 2 __author__ = 'weimw' 3  4 import requests 5 from BeautifulSoup import BeautifulSoup 6  7 def request_ctf5(): 8     f = open("out.txt", "w") 9     for i in range(1, 2000):10         url = 'http://ctf5.simplexue.com/8/index.php?id=' + str(i)11         res = requests.get(url)12         res_table = BeautifulSoup(res.content).find('table')13         tr_1 = res_table.findAll('tr')[0]14         try:15             tr_2 = res_table.findAll('tr')[1]16         except:17             print >> f, "no id and content"18             continue19         id_t = tr_2.findAll('td')[0].text20         content_t = tr_2.findAll('td')[1].text21         if id_t and content_t:22             print >> f, "id = %s, content = %s" % (id_t, content_t)23     return24 25 if __name__ == '__main__':26     request_ctf5()

不断修改id访问URL2000次，分析返回的页面。